2[t-(4t+16)+6]=2(t+10)

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Solution for 2[t-(4t+16)+6]=2(t+10) equation:


Simplifying
2[t + -1(4t + 16) + 6] = 2(t + 10)

Reorder the terms:
2[t + -1(16 + 4t) + 6] = 2(t + 10)
2[t + (16 * -1 + 4t * -1) + 6] = 2(t + 10)
2[t + (-16 + -4t) + 6] = 2(t + 10)

Reorder the terms:
2[-16 + 6 + t + -4t] = 2(t + 10)

Combine like terms: -16 + 6 = -10
2[-10 + t + -4t] = 2(t + 10)

Combine like terms: t + -4t = -3t
2[-10 + -3t] = 2(t + 10)
[-10 * 2 + -3t * 2] = 2(t + 10)
[-20 + -6t] = 2(t + 10)

Reorder the terms:
-20 + -6t = 2(10 + t)
-20 + -6t = (10 * 2 + t * 2)
-20 + -6t = (20 + 2t)

Solving
-20 + -6t = 20 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-20 + -6t + -2t = 20 + 2t + -2t

Combine like terms: -6t + -2t = -8t
-20 + -8t = 20 + 2t + -2t

Combine like terms: 2t + -2t = 0
-20 + -8t = 20 + 0
-20 + -8t = 20

Add '20' to each side of the equation.
-20 + 20 + -8t = 20 + 20

Combine like terms: -20 + 20 = 0
0 + -8t = 20 + 20
-8t = 20 + 20

Combine like terms: 20 + 20 = 40
-8t = 40

Divide each side by '-8'.
t = -5

Simplifying
t = -5

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